n^2+31n=0

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Solution for n^2+31n=0 equation: 



n^2+31n=0

a = 1; b = 31; c = 0;
Δ = b2-4ac
Δ = 312-4·1·0
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-31}{2*1}=\frac{-62}{2}
=-31
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+31}{2*1}=\frac{0}{2}
=0
$

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